(2x^2-5x-12)/(2x^2-4x-16)

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Solution for (2x^2-5x-12)/(2x^2-4x-16) equation:


D( x )

2*x^2-(4*x)-16 = 0

2*x^2-(4*x)-16 = 0

2*x^2-(4*x)-16 = 0

2*x^2-4*x-16 = 0

2*x^2-4*x-16 = 0

DELTA = (-4)^2-(-16*2*4)

DELTA = 144

DELTA > 0

x = (144^(1/2)+4)/(2*2) or x = (4-144^(1/2))/(2*2)

x = 4 or x = -2

x in (-oo:-2) U (-2:4) U (4:+oo)

(2*x^2-(5*x)-12)/(2*x^2-(4*x)-16) = 0

(2*x^2-5*x-12)/(2*x^2-4*x-16) = 0

2*x^2-5*x-12 = 0

2*x^2-5*x-12 = 0

DELTA = (-5)^2-(-12*2*4)

DELTA = 121

DELTA > 0

x = (121^(1/2)+5)/(2*2) or x = (5-121^(1/2))/(2*2)

x = 4 or x = -3/2

(x+3/2)*(x-4) = 0

2*x^2-4*x-16 = 0

2*(x^2-2*x-8) = 0

x^2-2*x-8 = 0

DELTA = (-2)^2-(-8*1*4)

DELTA = 36

DELTA > 0

x = (36^(1/2)+2)/(1*2) or x = (2-36^(1/2))/(1*2)

x = 4 or x = -2

2*(x+2)*(x-4) = 0

((x+3/2)*(x-4))/(2*(x+2)*(x-4)) = 0

( x+3/2 )

x+3/2 = 0 // - 3/2

x = -3/2

( x-4 )

x-4 = 0 // + 4

x = 4

x in { 4}

x = -3/2

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